Find the value of x in which (5x+4),(4x-5)and(2x-2) are in AP

Question

asked Dec 1, 2024 47.6k views

1 Answer

Xwrs · Answer 1 · 2024-12-05T15:20:13+0000

Answer: 12

Step-by-step explanation:

For AP d=u₂-u₁

therefor taking u₁= 5x+4

u₂= 4x-5

u₃ = 2x-2

u₂-u₁ = u₃-u₂

4x-5 -(5x+4) = 2x-2-(4x-5)

grouping like terms all Xs to the LHS and all numbers on the RHS

4x-5x-2x+4x = -2+5+5+4

By using a calculator, you get

X=12