Question

Find the distance between the points (3, – 4) and (3, – 9).

Answer 1

To find the distance between two points, we can use the distance formula in a 2D coordinate plane:

$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$

Given the points (3, – 4) and (3, – 9), we can substitute the values into the formula:

$$d = \sqrt{(3 - 3)^2 + (-9 - (-4))^2}$$

Simplifying further:

$$d = \sqrt{0^2 + (-5)^2}$$

Calculating:

$$d = \sqrt{0 + 25}$$

Therefore, the distance between the points (3, – 4) and (3, – 9) is approximately **5 units**.

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Answer 2

To find the distance between two points, (x₁, y₁) and (x₂, y₂), you can use the distance formula:

Distance = √((x₂ - x₁)² + (y₂ - y₁)²)

In your case, the points are (3, -4) and (3, -9). Plug these values into the formula:

Distance = √((3 - 3)² + (-9 - (-4))²)

Now, simplify:

Distance = √(0² + (-5)²)

Distance = √(0 + 25)

Distance = √25

Distance = 5

So, the distance between the points (3, -4) and (3, -9) is 5 units.

Explanation:

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