Question

What distance is required for a train to stop if its initial velocity is 23 m/s and its deceleration is 0.50 m/s2? (Assume the train slows down at a constant rate.)

Answer 1

Step-by-step explanation:

Given:

u = 23 m/s

v = 0 m/s

a = -0.50 m/s²

Find: s

v² = u² + 2as

(0)² = (23)² + 2(-0.50)s

s = 529 m

Rounded to two significant figures, the train stops after 530 meters.