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Answer: The surface charge density of an infinite charged sheet is 1 μC/m². How far apart are the equipotential surfaces whose potentials differ by 10 volts?

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User Sejal
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1 Answer

1 vote

Explanation: To solve this problem, we need to use the formula for the electric field strength between two charged objects:

E = k * (q1 * q2 / r^2)

where k is the electrostatic constant, q1 and q2 are the charges on the objects, and r is the distance between them. Since we have an infinite sheet of charge, we can treat it as a continuous distribution of charge. Therefore, we can integrate the electric field over a small area around each equipotential surface to find the average electric field strength:

Eavg = k * (σ / ε₀)

where σ is the surface charge density and ε₀ is the permittivity of free space. Substituting the given values, we get:

Eavg = k *

answered
User Ayser
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8.4k points
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