Let's use algebra to solve this problem. Let A represent Aciro's current age and let N represent Anena's current age.
We have two pieces of information:
1. Anena is 10 years older than Aciro, so N = A + 10.
2. At twenty years, Anena is twice as old as Aciro, so N + 20 = 2(A + 20).
Now, we can use these equations to solve for their ages. First, we'll substitute the value of N from the first equation into the second equation:
(A + 10) + 20 = 2(A + 20).
Now, we'll solve for A:
A + 30 = 2A + 40.
Subtract A from both sides:
30 = A + 40 - A.
30 = A + 40 - A simplifies to:
30 = 40 - A.
Now, subtract 40 from both sides:
-10 = -A.
Divide by -1 to isolate A:
A = 10.
So, Aciro is currently 10 years old.
Now, we can find Anena's age using the first equation:
N = A + 10,
N = 10 + 10,
N = 20.
Anena is currently 20 years old.