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2 votes
A ball is thrown horizontally from the top of

a building 140 m high. The ball strikes the
ground 54 m horizontally from the point of
release.
What is the speed of the ball just before it
strikes the ground?
Answer in units of m/s.

asked
User Euli
by
8.1k points

1 Answer

3 votes

Answer:

v = d / t = 54 / 5.34 = 10.11 m/s (rounded to two decimal places)

Step-by-step explanation:

answered
User Matthew Peters
by
8.7k points

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