asked 22.6k views
5 votes
The heat of fusion of ice is 334j/g. When a 10g pice of ice is placed in water melts. How much heat did the ice absorb?

asked
User Satyan
by
8.2k points

1 Answer

6 votes

Answer:

To calculate the amount of heat absorbed by the ice as it melts, you can use the formula:

Q = m * ΔH

Where:

Q is the heat energy absorbed (in joules).

m is the mass of the substance (in grams).

ΔH is the heat of fusion (in joules per gram).

Given that the heat of fusion of ice (ΔH) is 334 J/g and the mass of the ice (m) is 10 grams, you can calculate the heat absorbed (Q) as follows:

Q = 10 g * 334 J/g = 3,340 joules

So, the ice absorbed 3,340 joules of heat energy as it melted.

Step-by-step explanation:

answered
User Spunky
by
8.1k points
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