Question

A car is moving with a velocity of 10√2 m/s in the north-east direction. What are the components of its velocity along the east direction and north direction? A) East direction: 10 m/s, North direction: 10√2 m/s B) East direction: 10√2 m/s, North direction: 10 m/s C) East direction: 5 m/s, North direction: 5√2 m/s D) East direction: 5√2 m/s, North direction: 5 m/s

Answer 1

To find the components of the car's velocity along the east and north directions, we can use trigonometry.

Step-by-step explanation:

To find the components of the car's velocity along the east and north directions, we can use trigonometry. The velocity vector is 10√2 m/s in the north-east direction, which forms a 45-degree angle with both the east and north directions. Using the sine and cosine functions, we can determine the components as follows:

East direction: 10√2 m/s × cos(45°) = 10 m/s

North direction: 10√2 m/s × sin(45°) = 10√2 m/s

Therefore, the correct answer is East direction: 10 m/s, North direction: 10√2 m/s (option A).

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