Question

Suppose there is a 1.3 ° F drop in temperature for every thousand feet that an airplane climbs into the sky. The temperature on the ground is -2.8 ° F . Write a multiplication equation to represent the change in temperature after the plane ascends 10,000 feet

Answer 1

T, the metamorphosis of temperature (in degrees Fahrenheit), is to be thusly expressed:

T = (-2.8°F) - (1.3°F/1000 ft) * 10,000 ft

Now, permit me to unravel the equation's intricate threads:

Commence with the initial temperature, which upon the terrestrial plane is -2.8 degrees Fahrenheit.

In accordance with the sacred knowledge imparted, we ascertain the decreed temperature drop for each thousand-foot ascent, a grievous 1.3 degrees Fahrenheit.

As the vessel's ascent is of grandiose stature, extending 10,000 feet skyward, we must reckon the toll of this heightening endeavor. Multiply the temperature's descent per thousand feet (1.3°F) by the grand measure of 10.

The final act, a subtraction most somber, as we subtract the outcome of step 3 from the initial temperature, thereby revealing the metamorphosis, T.

Now, let us unravel T:

T = (-2.8°F) - (1.3°F/1000 ft) * 10,000 ft

T = (-2.8°F) - (1.3°F) * 10

T = -2.8°F - 13°F

T = -15.8°F

Thus, the temperature's transformation, as the airborne vessel soars to 10,000 feet, is unveiled as a chilling descent of -15.8 degrees Fahrenheit, akin to the very breath of winter's chill.