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The gauge pressure inside a pressure cooker is 13psi. What is the net force on the lid of the pressure cooker if the lid's area is 110 square inches?

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Final answer:

The net force on the lid of the pressure cooker, given the pressure and the lid area, is calculated using the formula F = P * A which yields 1430 pounds.

Step-by-step explanation:

The net force exerted on the lid of a pressure cooker is found using the equation F = P * A, where F is force, P is pressure, and A is area. In this case, the gauge pressure (P) is 13 psi and the area (A) of the lid is 110 square inches. So, plug these values into the equation giving F = 13 psi * 110 square inches. Thus, the net force is 1430 pounds. As a result, this is the amount of force acting downwards on the cooker's lid due to the pressure inside the cooker.

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