Determine the first partial derivatives of g(x, y, z) = 5ln (2xy/7z). ∂f/ ∂x = ∂f/ ∂y= ∂f/∂z=

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asked Oct 5, 2024 149k views

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Akshay Bagade · Answer 1 · 2024-10-11T23:12:55+0000

To determine the first partial derivatives of g(x, y, z) = 5ln (2xy/7z), we can calculate them individually.

∂g/∂x = (5/2) * (1/x)

∂g/∂y = (5/2) * (1/y)

∂g/∂z = (-5/7) * (1/z)

Determine the first partial derivatives of g(x, y, z) = 5ln (2xy/7z). ∂f/ ∂x = ∂f/ ∂y= ∂f/∂z=

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