Question

Find the real roots of the equation by 6x^(2)-x-7=0

Answer 1

6x^2-x-7=0

let's find the roots using the discriminant formula:

a=6, b=-1, c=-7


D= b^2-4ac => 1-4*6*(-7) = 1+168 = 169, D>0


x1,2= -b±√D/2a => 1±13/12 = 7/6; -1


-1; 7/6