Question

Blocks X and Y are attached to each other by a light rope and can slide along a horizontal, rough surface. Block X has YX Fwo a mass of 10 kg and block Y a mass of 5 kg. An applied force of 36.N [night] acts on block X. Suppose the magnitude of the force of fnction on blocks X and Y are 8N and 4N respectively. The magnitude of tension in the string between the blocks is a. 36 N b. 12 N c. 4 N d. 18 N

Answer 1

Using Newton's second law and the given information, we calculate the acceleration of the whole system first, then with consideration of block Y alone, we determine the magnitude of tension in the rope is 12N.

Step-by-step explanation:

In this physics problem, we have two blocks, X and Y, sliding along a rough surface connected by a light rope. The problem is asking us to determine the magnitude of the tension in the rope among them. There's an applied force of 36N acting on block X, and both blocks are subject to friction.

Firstly, let's find the acceleration of the system by dividing the net force (applied force - total friction) by the total mass of the system. This turns out to be (36N - (8N + 4N)) / (10kg + 5kg) = 1.6 m/s².

Next, let's consider block Y alone. There are two forces acting on Block Y: the tension in the rope (unknown) and the friction (4N). And since the block is moving with an acceleration, we can write Newton's second law: tension = mass of block Y * acceleration + friction on Y. By substituting respective values, we'll have tension = 5kg * 1.6m/s² + 4N = 12N.

So the magnitude of tension in the string between the blocks is 12N (option b).

Answer: . 12 N

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