Question

The quadratic formula to were to the nearest tenth. x^(2)-10x+3=0

Answer 1

Plug a = 1, b = -10, c = 3 into the quadratic formula.

`x = (-b\pm√(b^2-4ac))/(2a)\\\\x = (-(-10)\pm√((-10)^2-4(1)(3)))/(2(1))\\\\x = (10\pm√(100 - 12))/(2)\\\\x = (10\pm√(88))/(2)\\\\x \approx (10\pm9.380832)/(2)\\\\x \approx (10+9.380832)/(2) \ \text{ or } \ x \approx (10-9.380832)/(2)\\\\x \approx (19.380832)/(2) \ \text{ or } \ x \approx (0.619168)/(2)\\\\x \approx 9.690416 \ \text{ or } \ x \approx 0.309584\\\\x \approx 9.7 \ \text{ or } \ x \approx 0.3\\\\`

Answers: x = 9.7 and x = 0.3