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Arrange the following from lowest to highest entropy: HgS(8), HgCl()Hg,C1, (s), HgO(s). Assume 1 mole of each at the same conditions from lowest to highest entropy Drag and drop your selection from the following list to complete the answer Hg, Cl(s) HgS(8) HgC1,6) HgO()

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User Schtopps
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1 Answer

7 votes

Final answer:

The correct order from lowest to highest entropy is HgS(s) < HgCl2(s) < HgO(s) < Hg(g).

Step-by-step explanation:

The entropy of a system is a measure of the degree of disorder or randomness in that system. The higher the entropy, the system gets more chaotic. In general, solids have lower entropy than liquids, which have lower entropy than gases.

Now let's arrange the given compounds from lowest to highest entropy:

HgS(s) - This is a solid compound, so it has the lowest entropy.

HgCl2(s) - This is also a solid compound, so its entropy is higher than HgS, but lower than the remaining compounds.

HgO(s) - This is another solid compound, so its entropy is higher than HgS and HgCl2, but lower than the last compound.

Hg(g) - This is a gas, so it has the highest entropy among the given compounds.

Therefore, the correct order from lowest to highest entropy is: HgS(s) < HgCl2(s) < HgO(s) < Hg(g).

answered
User Merlene
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