Question

Use these two constants for the question that follows: e = 1.6 × 10−19 c k = 8.99 × 109 n m² /c² two negative charges are 10−14 m away from each other. using coulomb's law, which of the following is the electrical force between these two particles? a. 2.3 n b. −2.3 n c. 1.4 n d.−1.4 n

Answer 1

Using Coulomb's law and substituting the given values, the electrical force between two negative charges 10^-14 m apart is found to be 2.3 N (option A), which is repulsive in nature.

To calculate the electrical force between two negative charges using Coulomb's law, we use the formula:

F = k * |q1 * q2| / r^2

where F is the force between the charges, k is Coulomb's constant (8.99 × 10^9 N m^2/C^2), q1 and q2 are the amounts of the charges (each 1.6 × 10^-19 C), and r is the distance between the charges (10^-14 m). Substituting the values, we get:

F = (8.99 × 10^9 N m^2/C^2) * (1.6 × 10^-19 C)^2 / (10^-14 m)^2.

When calculating this, the result is:

F = 2.3 N.

Since both charges are negative, the force will be repulsive, which means in the selected options, the correct magnitude of force without the sign is needed. Therefore, the correct answer is A) 2.3 N.