Question

John has received scores of 85,88,87, and 95 on her algebra tests. What is the minimum score he must receive on the fifth test to have an overall test score average of at least 90 ? (Hint: The average of a list of numbers is their sum divided by the number of numbers )

Answer 1

Explanation:

The score for the fifth test is what we are looking for, so we'll call that x. Therefore,

`(85+88+87+95+x)/(5)\geq 90` and multiply both sides by 5 to get

355 + x ≥ 450 and

x ≥ 95

John needs at least a 95 on his fifth test to get a 90 in the class.