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5 years ago a man's age was 5 times the age of his daughter 3yrs hence twice his age will be equal to 6 times his daughter age find their present age

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User Praneeta
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1 Answer

3 votes

Answer:

present age of man = 45 years

present age of daughter = 13 years

Explanation:

let present age of man = x, and

present age of daughter = y

according to the question:

5 years ago man's age was 5 times the age of his daughter,

x - 5 = 5(y - 5)

x - 5 = 5y - 25

x = 5y - 25 + 5

x = 5y - 20 (1)

in 3 years time twice of man's age will be equal to 6 times his daughter's age,

2(x + 3) = 6(y + 3)

2x + 6 = 6y + 18

2x = 6y + 18 - 6

2x = 6y + 12

x = 6y + 12 / 2 (2)

by comparing both equations (1) and (2)

5y - 20 = 6y + 12 / 2

10y - 40 = 6y + 12

10y - 6y = 12 + 40

4y = 52

y = 52/4 = 13

by substituting the value of y in equation (1)

x = 5(13) - 20

= 65 - 20

= 45

thus the present ages are,

man, x = 45 years

daughter, y = 13 years

answered
User Markfickett
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8.0k points