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for a moving object the force acting on the object varies directly with the object’s acceleration. when a force of 36 N acts on a certain object the acceleration of the object is 4 m/s^2. if the force is changed to 54 N what will be the acceleration of the object

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Answer:

According to the conditions given in the question, the force acting on the object varies directly with its acceleration. This means that the force experienced by the object is proportional to its acceleration, and can be represented by the equation: F = ka where F is the force, k is some constant, and a is the acceleration. In the problem given, the force is given as 36 N and the acceleration as 4 m/s^2, so we can rearrange the equation to solve for a: a = F/k = 36 N / k = 36/k m/s^2 Now we need to find the value of k, the constant which represents the proportionality between the force and the acceleration. We know that the new force will be 54 N, and we want to find the acceleration that results from a force of 54 N. Plugging in the values, we get: a = 54 N / k Solve for k: k = 54 N/a = 54 N/4 m/s^2 = 13.5 m/s^2 We can now use the equation F = ka to find the acceleration when the force is 54 N: a = F/k = (54 N)/(13.5 m/s^2) = 4.0 m/s^2 So the acceleration when the force is changed to 54 N is still 4 m/s^2.

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