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find the equation of the line that is parallel to the line y=5x+6 and passes through the point (2,-8). write the equation in point slope form

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User Chmike
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2 Answers

3 votes

Answer: y + 8 = 5(x - 2)

Explanation:

Two lines that are parallel to each other have the same slope. The line we're given is in slope-intercept form, y=mx+b, where m is the slope.

With y=5x+6, m=5, so our slope = 5.

Point-slope form is y - y1 = m(x - x1), with m being the slope and x1 and y1 coming from a given point.

Our given point is (2,-8), so x1 = 2 and y1 = -8.

Next, plug in our values into point-slope form:

y - y1 = m(x - x1)

y - (-8) = 5(x - 2)

y + 8 = 5(x - 2)

I hope this helped! :)

answered
User Ididak
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7.7k points
3 votes

How do you write the equation of a point slope form passing through (-2,8) and parallel to the line 5x−6y−7=0?

Answer: y=56x+293

answered
User Angella
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8.2k points

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