Question

27 = 3c -3 (6 - 2c)

pls help !

with step by step explanation pls!

Answer 1

Answer: c = 5

Explanation:

In order to solve this equation, isolate c.

Given equation:

`\sf{3c-3(6-2c)=27}`

Distribute 3:

`\sf{3c-18+6c=27}`

Combine like terms:

`\sf{3c+6c-18=27}`

`\sf{9c-18=27}`

Add 18 to both sides:

`\sf{9c=45}`

Divide both sides by 9:

`\sf{c=5}`