Question

What is the equation of the line that is perpendicular to y = negative two-thirds x + 4 and that passes through (–2,–2)?

On a coordinate plane, a line goes through (3, 2), and (6, 0). A point is at (negative 2, negative 2).
y = three-halves x minus StartFraction 10 Over 3 EndFraction
y = three-halves x minus 5
y = three-halves x + 1
y = three-halves x minus two-thirds

Answer 1

y = - 2/3x + 4
point (-2, -2)
Slope -2/3 (slope of the perpendicular line = 3/2 (positive inverse)
y-y = slope(x-x)
y - -2 = 3/2 (x - - 2)
y + 2 = 3/2 (x + 2)
y + 2 = 3/2x + 3/2*2
y +2 = 3/2x + 3
y = 3/2x +3-2
y = 3/2x +1