Question

A student received scores of 44, 48, and 76 on three quizzes. His sister received scores of 48, 57, and 63. Who had the better average?

Answer 1

They have the same average.

Explanation:

To find the average of each person, add all the scores and divide by how many quizzes they took.

Student) 44+48+76 = 168

He took 3 quizzes, so divide 168 by 3.

168/3 = 56. The student's average is 56.

Now let's check his sister

Sister) 48+57+63 = 168

She also took 3 quizzes so divide 168 by 3.

168/3 = 56. The sister's average is 56.

56=56

Answer 2

To determine who had the better average, let's calculate the average scores for both the student and his sister:

For the student:

Average = (44 + 48 + 76) / 3 = 168 / 3 = 56

For the sister:

Average = (48 + 57 + 63) / 3 = 168 / 3 = 56

Both the student and his sister have the same average score of 56. So, they have an equal average performance on their quizzes.