Question

Determine the molar mass of cesium phosphate.

Determine how many moles are in 15.6 grams of cesium phosphate.
Determine What quantity in moles of cesium are in 15.6 grams of cesium phosphate.
How many atoms of cesium are in 15.6 grams of cesium phosphate?

Answer 1

The molar mass of cesium phosphate is 414.9 g/mol. There are 0.0376 moles and 2.26 x 10^22 atoms of cesium in 15.6 grams of cesium phosphate.

Step-by-step explanation:

The molar mass of cesium phosphate (Cs3PO4) can be calculated by adding up the molar masses of its constituent elements. The molar mass of cesium (Cs) is 132.9 g/mol, phosphorus (P) is 31.0 g/mol, and oxygen (O) is 16.0 g/mol. Therefore, the molar mass of cesium phosphate is:

3 x 132.9 g/mol (for cesium) + 1 x 31.0 g/mol (for phosphorus) + 4 x 16.0 g/mol (for oxygen) = 414.9 g/mol.

To determine the number of moles in 15.6 grams of cesium phosphate, you can use the formula:

Moles = Mass / Molar mass.

Substituting the values, we get:

Moles = 15.6 g / 414.9 g/mol = 0.0376 moles.

Since cesium phosphate contains 3 moles of cesium per mole of the compound, we can calculate the quantity in moles of cesium by multiplying the number of moles of cesium phosphate by the ratio of cesium to cesium phosphate. Therefore:

0.0376 moles x (3 moles cesium / 1 mole cesium phosphate) = 0.1128 moles of cesium.

To find the number of atoms of cesium in 15.6 grams of cesium phosphate, we can use Avogadro's number (6.022 x 10^23 atoms/mol). The number of atoms is given by:

Number of atoms = Moles x Avogadro's number.

Substituting the values, we get:

Number of atoms = 0.0376 moles x (6.022 x 10^23 atoms/mol) = 2.26 x 10^22 atoms.

Answer 2

The molar mass of cesium phosphate is 493.70 g/mol. There are approximately 0.0316 moles of cesium phosphate and 0.0948 moles of cesium in 15.6 grams of cesium phosphate, which amounts to about 5.70 x 10^22 atoms of cesium.

Step-by-step explanation:

To determine the molar mass of cesium phosphate, we must first know its chemical formula, which is Cs3PO4. This compound contains 3 cesium (Cs) atoms, 1 phosphorus (P) atom, and 4 oxygen (O) atoms. Using the periodic table, we can find the atomic masses for cesium (132.91 g/mol), phosphorus (30.97 g/mol), and oxygen (16.00 g/mol).

The molar mass is calculated as follows: Molar mass = (3 x 132.91 g/mol) + (1 x 30.97 g/mol) + (4 x 16.00 g/mol) = 398.73 + 30.97 + 64.00 = 493.70 g/mol.

To find out how many moles are in 15.6 grams of cesium phosphate, we use the formula: Moles = mass (g) / molar mass (g/mol). So, Moles = 15.6 g / 493.70 g/mol ≈ 0.0316 moles of cesium phosphate.

Since there are 3 moles of cesium for every mole of cesium phosphate, the number of moles of cesium in 15.6 grams of cesium phosphate is 3 x 0.0316 moles ≈ 0.0948 moles of cesium.

To determine the number of atoms of cesium, we multiply the moles of cesium by Avogadro's number (6.022 x 1023 atoms/mol): 0.0948 moles x 6.022 x 1023 atoms/mol ≈ 5.70 x 1022 atoms of cesium.