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What is the slope of a line that is perpendicular to the line whose equation is 8y−5x=11 ? a. −85 b. 85 c. 57 d. −75

asked
User Filsh
by
7.6k points

1 Answer

6 votes

Answer:

-5x + 8y = 11

8y = 5x + 11

y = (5/8)x + (11/8)

The slope of a line perpendicular to this line is -8/5.

The correct answer is A.

answered
User Balaji V
by
8.3k points
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