Question

QUADRATIC EQUATION

5v(2v - 4) = -12
Solution:​

Answer 1

.....5v(2v - 4) = -12

10v²-20v+12 =0

a=10 ; b=−20 ; c=12

b²-4ac =(-20)²-4(10*12)=-80

Δ is strictly negative, the equation 10x²−20x+12= does not admit any solution in R

Explanation:

Answer 2

Hello!

Answer:

`\Large \boxed{\sf No ~real~ solution}`

Explanation:

→ We want to solve this equation:

`\sf 5v(2v - 4) = -12`

◼ Simplify the left side:

`\sf 10v^2 - 20v= -12`

◼ Add 12 to both sides:

`\sf 10v^2 - 20v+12= -12+12`

◼ Simplify both sides:

`\sf 10v^2 - 20v+12= 0`

→ It's a quadratic equation because it's on the form ax² + bx + c = 0.

→ To solve a quadratic equation, we have the quadratic formula:

`\sf x = (-b\pm√(b^2 - 4ac) )/(2a)`

In our equation:

`\sf a = 10\\b = -20\\c = 12`

◼ Let's apply the quadratic formula:

`\sf x = (-(-20)\pm√((-20)^2 - 4(10)(12)) )/(2(10))`

◼ Simplify the equation:

`\sf x = (20\pm√(-80) )/(20)`

→ The solution has no real solution because the Δ (b² - 4ac) is < 0.

Conclusion:

The equation 5v(2v - 4) = -12 has no real solution.