Answer:
a₁₅ = 87
Explanation:
there is a common difference between consecutive terms in the sequence , that is
48 - 45 = 51 - 48 = 54 - 51 = 3
this indicates the sequence is arithmetic with nth term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
here a₁ = 45 and d = 3 , then
a₁₅ = 45 + (14 × 3) = 45 + 42 = 87