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1 vote
Subtract (9a^2 - 7b + 3c^3 - 4) - (6a^2 + 6b - 3c^3 - 4)

1 Answer

4 votes

Answer:

6c^3 + 3a^2 - 13b

Explanation:

To make this problem simpler, let's just make the numbers in the second set of parentheses all the opposite of each other since we're subtracting it from the first set of parentheses.

(9a^2 - 7b + 3c^3 - 4) - (6a^2 + 6b - 3c^3 - 4)

(6a^2 + 6b - 3c^3 - 4) becomes:

-6a^2 - 6b + 3c^3 + 4

Now let's solve the problem:

9a^2 - 7b + 3c^3 - 4 - 6a^2 - 6b + 3c^3 + 4

Combine the like terms:

(9a^2 - 6a^2) + (-7b - 6b) + (3c^3 + 3c^3) (-4 + 4)

= 3a^2 - 13b + 6c^3

Rearrange:

6c^3 + 3a^2 - 13b

answered
User Arun Siva
by
8.0k points
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