Question

( x - y + z ) (x + y )


full procedure please​

Answer 1

`x^(2)` + zx -
`y^(2)` + zy

Explanation:

It's easier (in my opinion) to format it like so:

(x + y) (x - y + z)

now, we'll distribute the x and y in the first parenthesis to the x, y, and z in the second parenthesis. do them individually first

(
`x^(2)` - yx + zx) + (yx -
`y^(2)` + zy)

now, combine any like terms

`x^(2)` + zx -
`y^(2)` + zy