A^2+6a+9,a^2-9 find the fraction

Question

asked Jun 16, 2024 77.4k views

1 Answer

Pradeep Gollakota · Answer 1 · 2024-06-20T07:25:34+0000

Hello!

Answer:

$\Large \boxed{\sf (a+3)/(a-3)}$

Explanation:

→ We want to simplify this expression:

$\sf (a^2+6a+9)/(a^2-9)$

◼ Factor the numerator and denominator:

$\sf ((a+3)^2)/(a^2-9)$

$\sf ((a+3)(a+3))/((a+3)(a-3))$

◼ Cancel out the common factors:

$\sf (a+3)/(a-3)$

Conclusion:

The expression (a²+6a+9)/(a²-9) is equal to (a+3)/(a-3).