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Question olve the following quadratic by factoring. a^(2)-4a-12=0

1 Answer

4 votes

Answer:

a = - 2 , a = 6

Explanation:

a² - 4a - 12 = 0

consider the factors of the constant term (- 12) which sum to give the coefficient of the a- term (- 4)

the factors are + 2 and - 6, since

+ 2 × - 6 = - 12 and + 2 - 6 = - 4

use these factors to split the a- term

a² + 2a - 6a - 12 = 0 ( factor the first/second and third/fourth terms )

a(a + 2) - 6(a + 2) = 0 ← factor out common factor (a + 2) from each term

(a + 2)(a - 6) = 0 ← in factored form

equate each factor to zero and solve for a

a + 2 = 0 ( subtract 2 from each side )

a = - 2

a - 6 = 0 ( add 6 to both sides )

a = 6

solutions are a = - 2 , a = 6

answered
User Mehmetdemiray
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