Question

A new community sports complex is being built in pagosa springs. The perimeter of the rectangular playing field is 508 yards. The length of the field is 6 yards less than quadruple the width. What are the dimensions of the playing field?

Answer 1

We have the equation:
508 = 2(4w - 6 + w)

Simplify it:
508 = 2(5w - 6)
508 = 10w - 12

Now, isolate "w" by adding 12 to both sides:
10w = 520

Divide both sides by 10:
w = 52

So, the width of the playing field is 52 yards. Now plug this value into the expression for the length:
Length = 4w - 6
Length = 4 * 52 - 6
Length = 208 - 6
Length = 202 yards

The dimensions of the playing field are 52 yards in width and 202 yards in length.