Question

Graph the lIne with slope -2 passing through the point(-4, 4).​

Answer 1

Answer: Below

Before graphing, we will first find the line's equation.

We know that it has a slope of -2 and that it passes through the point (4,4), so, we can pug these values into the

`y-y_1=m(x-x_1)`

`y-4=-2(x-(-4)}`

`y-4=-2(x+4)`

We can now graph it.

Answer 2

Step-by-step explanation: To graph the line with a slope of -2 passing through the point (-4, 4), you can use the point-slope form of a linear equation.

The point-slope form of a linear equation is y - y1 = m(x - x1), where (x1, y1) represents a point on the line and m represents the slope of the line.

In this case, the given point is (-4, 4) and the slope is -2. Plugging these values into the point-slope form, we get:

y - 4 = -2(x - (-4))

Simplifying the equation:

y - 4 = -2(x + 4)

y - 4 = -2x - 8

Now, let's rearrange the equation in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept:

y = -2x - 4

This equation tells us that the line has a slope of -2 and a y-intercept of -4.

To graph the line, plot the given point (-4, 4) on the coordinate plane. Then, use the slope to find additional points on the line. Since the slope is -2, we can move 1 unit to the right and 2 units down from the given point to find another point. Repeat this process to find more points if needed.

Once you have a few points, connect them with a straight line. The resulting line will have a slope of -2 and pass through the point (-4, 4).

I hope this helps! Let me know if you have any further questions.