Answer:
Total Resistance ≈ 34832 Ω
Total Current ≈ 0.000344 A
Voltage Drop across R1 ≈ 0.10624 V
Voltage Drop across R2 ≈ 0.172 V
Voltage Drop across R3 ≈ 11.70448 V
Step-by-step explanation:
To find the total resistance of a series circuit, you simply add up the individual resistances:
Total Resistance (R_total) = R1 + R2 + R3
Given the resistances:
R1 = 310 Ω
R2 = 500 Ω
R3 = 34022 Ω
Total Resistance = 310 Ω + 500 Ω + 34022 Ω
Total Resistance ≈ 34832 Ω
Now, to find the current through each resistor in a series circuit, you can use Ohm's Law:
Current (I) = Voltage (V) / Resistance (R)
Since the battery voltage is 12V and the total resistance is 34832 Ω, you can calculate the total current:
Total Current = 12 V / 34832 Ω
Total Current ≈ 0.000344 A
Since the circuit is a series circuit, the same current flows through all the resistors:
Current through each resistor = Total Current
Current through each resistor ≈ 0.000344 A
To find the voltage drop across each resistor, you can use Ohm's Law again:
Voltage Drop (V_drop) = Current (I) × Resistance (R)
For each resistor:
Voltage Drop across R1 = Current × R1
Voltage Drop across R2 = Current × R2
Voltage Drop across R3 = Current × R3
Voltage Drop across R1 ≈ 0.000344 A × 310 Ω
Voltage Drop across R2 ≈ 0.000344 A × 500 Ω
Voltage Drop across R3 ≈ 0.000344 A × 34022 Ω
Voltage Drop across R1 ≈ 0.10624 V
Voltage Drop across R2 ≈ 0.172 V
Voltage Drop across R3 ≈ 11.70448 V