Question

Resolve into partial fraction 3x +2/(x+2)(x-5)
​

Answer 1

Hi,

Explanation:

`(3x+2)/((x+2)(x-5)) =(A)/(x+2) +(B)/(x-5) =(Ax+Bx-5A+2B)/((x+2)(x-5)) \\\\\\\left\{\begin{array}{ccc}A+B&=&3\\-5A+2B&=&2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}7B&=&17\\-7A&=&-4\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}B&=&(17)/(7)\\\\A&=&(4)/(7)\\\end{array}\right.\\`

`(3x+2)/((x+2)(x-5)) =(4)/(7(x+2)) +(17)/(7(x-5))`