asked 194k views
5 votes
Question 2 (1 point)

Find mz1 and m<2. For angles that cannot be found write
"cannot be determined" or "CBD".
30°
m/1 =
1/2
f
m/2=
Blank 1:
Blank 2:

Question 2 (1 point) Find mz1 and m<2. For angles that cannot be found write &quot-example-1
asked
User Jourmand
by
8.2k points

1 Answer

4 votes

Answer:


\sf m \angle 1 = 160\degree


\sf m \angle 2= &nbsp;20\degree

Explanation:

Frm the given figure


\sf m \angle 2 and 20° are the Alternate exterior angles i.e they are equal.


\sf m \angle 2= &nbsp;20\degree

Also
\sf m \angle 1 and
\sf m \angle 2 are the linear angles whose sum is 180°


\sf m \angle 1 + m\angle 2 = 180\degree


\sf m \angle 1 + 20\degree = 180\degree

Subtract 20 from both sides,


\sf m \angle 1 + 20\degree &nbsp;- 20 = 180\degree - 20


\sf m \angle 1 = 160\degree

Therefore,


\sf m \angle 1 = 160\degree


\sf m \angle 2 = &nbsp;20\degree


\dotfill

answered
User Atm
by
9.0k points
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