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1 vote
Find the center and radius of the sphere x^2 - 20x – 3 + y^2 + 8y +z^2 - 10z = 0 OA.C(10,4,-5), r = 12 OB.C(-20,8,- 10), r = 3 OC.C(-10,4,5), r = 3 OD.C(10,- 4,5), r = 144 O E C(10,- 4,5), r = 12

1 Answer

3 votes

Answer:

Hi,

Answer E

Explanation:


\\x^2-20x-3+y^2+8y+z^2-10z=0\\\\x^2-2*10x+100+y^2+2*4y+16+z^2-2*5z+25-100-3-16-25=0\\\\(x-10)^2+(y+4)^2+(z-5)^2=12^2\\\\Center=(10,-4,5),\ radius=12\\Answer: E\\

answered
User Mike Richards
by
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