asked 37.4k views
5 votes
Randy dropped a bouncy ball from his apartment window from a height of 40ft. The ball always bounces 1/4 of the distance fallen. How far has the ball traveled once it is done​ bouncing?

asked
User Uuazed
by
7.9k points

2 Answers

4 votes
The ball has traveled a total distance of 53.33ft after it is done bouncing.
answered
User Cyrill
by
7.9k points
2 votes

Answer:

53.33 feet

Explanation:

Let's calculate the total distance the ball has traveled after bouncing.

The ball is dropped from a height of 40 feet. During the first fall, it travels the full distance of 40 feet.

Distance fallen = 40 feet

After the first fall, the ball bounces back up but only reaches 1/4 of the distance it fell during the previous fall.

Distance bounced back up = 1/4 * 40 feet = 10 feet

The ball then falls again from the height it bounced back up to (10 feet).

Distance fallen = 10 feet

After the second fall, the ball bounces up again but only reaches 1/4 of the distance it fell during the second fall.

Distance bounced back up = 1/4 * 10 feet = 2.5 feet

The ball then falls again from the height it bounced back up to (2.5 feet).

Distance fallen = 2.5 feet

This process of bouncing and falling repeats indefinitely, but each bounce becomes shorter and shorter as it is only 1/4 of the previous fall.

Now, to find the total distance traveled by the ball, we need to sum up the distances fallen and the distances bounced back up:

Total distance = 40 feet + 10 feet + 2.5 feet + ... (and so on, infinite series)

To calculate the infinite series, we can use the formula for the sum of an infinite geometric series:

Sum = a / (1 - r)

where 'a' is the first term (40 feet) and 'r' is the common ratio (1/4).

Sum = 40 / (1 - 1/4) = 40 / (3/4) = 40 * (4/3) = 160/3 ≈ 53.33 feet

So, the ball has traveled approximately 53.33 feet once it is done bouncing.

answered
User Camdub
by
7.1k points
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