Question

A natural gas tank is constructed so that the pressure remains constant. On a hot day when the temperature was 33°C, the volume of gas in the tank was determined to be 3000.0 L. What would the volume be on a warm day when the temperature is 14°C? Name the law that is used to solve this problem.

Answer 1

on a warm day when the temperature is 14°C, the volume of gas in the tank would be approximately 2811.0 L

Step-by-step explanation:

According to Charles's Law, we can write the equation:

V1 / T1 = V2 / T2

Where:

V1 = Initial volume of gas (3000.0 L)

T1 = Initial temperature (33°C + 273.15 K)

V2 = Final volume of gas (unknown)

T2 = Final temperature (14°C + 273.15 K)

Let's substitute the values into the equation and solve for V2:

3000.0 L / (33°C + 273.15 K) = V2 / (14°C + 273.15 K)

Simplifying the equation:

3000.0 L / 306.15 K = V2 / 287.15 K

Cross-multiplying:

3000.0 L * 287.15 K = V2 * 306.15 K

V2 = (3000.0 L * 287.15 K) / 306.15 K

Calculating the value:

V2 ≈ 2811.0 L

Therefore, on a warm day when the temperature is 14°C, the volume of gas in the tank would be approximately 2811.0 L.