Answer:
Explanation:
To find y-intercepts, we make x = 0
So for (a), log5(0-5) = log5(-5).
As the log of a negative number is undefined, then this graph has no y-intercept. (Im assuming log5 means log base 5)
Using the same method for (b) we get y = -1/2 for the intercept.
As for x-intercepts, make y=0. Part (a) requires some factorising but divide by 2 first.