Question

Different forces were applied to five balls, and each force was applied for the same amount of time. The data is in the table. A 4 column table with 3 rows. The first column is labeled Object with entries Ball A, Ball B, Ball C, Ball D. The second column is labeled Force in Newtons with entries 50 N, 60 N, 70 N, 80 N. The third column is labeled Time in seconds with entries 1.25, 1.25, 1.25, 1.25. The fourth column is labeled Impulse in Newtons times seconds with entries 62.5, 75, 87.5, 100. If the force on ball A doubles while the time remains the same, what happens to the impulse? It divides in half. It does not change. It doubles. It quadruples.

Answer 1

Comparing the new impulse (125 N·s) to the initial impulse (62.5 N·s), we can see that the new impulse is double the initial impulse.

So, the correct answer is: It doubles.

Step-by-step explanation:

When the force on Ball A doubles while the time remains the same, the impulse will also double. Impulse is calculated as the product of force and time:

Impulse = Force × Time

Initially, the impulse on Ball A was 62.5 N·s (Newtons times seconds). If the force on Ball A doubles, the new force would be 2 × 50 N = 100 N, and the time remains 1.25 seconds. Thus, the new impulse would be:

New Impulse = 100 N × 1.25 s = 125 N·s

Comparing the new impulse (125 N·s) to the initial impulse (62.5 N·s), we can see that the new impulse is double the initial impulse.

So, the correct answer is: It doubles.