Question

An airplane starts from rest and accelerates at a constant 4. 50m/s^2 for 35. 0s before leaving the ground. How far did it move

Answer 1

• 2756 m

Step-by-step explanation:

An airplane starts from rest and accelerates at a constant 4.50m/s² for 35.0 s before leaving the ground.

• An airplane starts from rest, So Initial velocity will be Zero.

• Acceleration is 4.50 m/s²

• Time taken by the aeroplane is 35 seconds.

From Second equation of motion,,

• s = ut + 1/2 at^2

Here,

• u - initial velocity
• t - time taken
• a - acceleration
• S - distance covered

Plugging the values,

=> S = 0(35)+ 1/2 (4.50)(35)²

=> S = 0 + 1/2 (4.50)( 1225)

=> S = 5512.5/2

=> S = 2756.25 m

Therefore, The airplane moves 2756 metres approximately.