Answer: 6 children
Explanation:
In this scenario, there were two buses for the sixth-grade class trip. However, one of the buses broke down, so all the children had to crowd onto the seats of the second bus. The children were distributed equally in terms of crowdedness. It is stated that three children were sitting on every 2 seats.
To find out how many children were sitting on the back seat, we need to know how many seats are on the back seat. In this case, it is mentioned that there are 4 seats on the back seat of the bus.
Since three children were sitting on every 2 seats, we can calculate the number of children sitting on the back seat by considering the ratio of seats to children.
If three children are sitting on every 2 seats, we can write this as a ratio: 3 children : 2 seats.
We can simplify this ratio by dividing both the number of children and seats by the greatest common divisor (GCD) of 3 and 2, which is 1. This gives us a simplified ratio of: 3 children : 2 seats.
Now, we can set up a proportion using the ratio of seats on the back seat (4 seats) to the number of children:
4 seats / x children = 2 seats / 3 children
To solve for x (the number of children sitting on the back seat), we cross-multiply and solve the equation:
4 seats * 3 children = 2 seats * x children
12 children = 2x
Dividing both sides by 2, we get:
x = 6
Therefore, there were 6 children sitting on the back seat of the bus.