Question

Which is the equation of the line that contains the point (-2,-5) and has a slope of -8 ?

Answer 1

I will give you this equation in three different forms.

y + 5 = -8(x + 2) point-slope form

y + 5 = -8x - 16

y = -8x - 21 slope-intercept form

8x + y = -21 standard form

Answer 2

• y = -8x - 21

Detailed explanation:

Hi there! Our task is to find the equation of the line, given that:

✦ slope = -8

✦ passes through (-2,-5)

↪ The next step is to plug the data into point-slope.

FORMULA:

`\pmb{y-y_1=m(x-x_1)}`

Where:

✦ m = slope

✦
`\sf{(x_1,y_1)` is a point on the graph

Plug in the data:

`\sf{y-(-5)=-8(x-(-2)}`

`\sf{y+5=-8(x+2)}`

`\sf{y+5=-8x-16}`

`\sf{y=-8x-16-5}`

`\sf{y=-8x-21}`

`\bigstar` Therefore, the equation is y = -8x - 21.