asked 204k views
1 vote
A basketball is thrown into the air. its height after t seconds can be modeled by �4t(4t � 5). simplify the expression �4t(4t � 5). �16t2 20t �16t 20 16t2 � 20t �16t2 � 20t

asked
User Corno
by
7.4k points

1 Answer

5 votes

h(t) = –16t^2 + 46*t + 6

Explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The projectile formula is

h(t) = -16*t^2 + v*t + h0

Where,

v = initial vertical velocity of the ball in feet per second

h0 = initial height of the ball in feet

We need to fill the equation

h(t) = –16t^2 + v*t + 6

Where

v is the missing speed

If we go through many values of v until we find the same graph as the one showed in the first picture, we can find that

v = 46 ft/s

answered
User Benjamin Hackl
by
8.3k points
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