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A floor 4.5 m long and 3.6 m wide is to be covered with tiles. A 6 cm square tile costs 23.25. What will be the cost to cover the floor with these tiles?​

2 Answers

5 votes

Answer:

To find the cost of covering the floor with tiles, we need to calculate the number of tiles required and then multiply it by the cost of each tile.

Explanation:

1. Calculate the area of the floor: The floor is 4.5 m long and 3.6 m wide, so the area can be found by multiplying these two dimensions:

Area = length x width = 4.5 m x 3.6 m = 16.2 square meters

2. Calculate the number of tiles needed: Since the tiles are 6 cm square, we need to convert the area of the floor to square centimeters before dividing it by the area of one tile:

Area in square centimeters = Area in square meters x (100 cm/1 m)^2

Area in square centimeters = 16.2 square meters x (100 cm/1 m)^2 = 16200 square centimeters

Number of tiles = Area in square centimeters / Area of one tile

Number of tiles = 16200 square centimeters / (6 cm x 6 cm) = 4500 tiles

3. Calculate the cost to cover the floor: Since each tile costs 23.25, we can multiply the number of tiles by the cost per tile to find the total cost:

Cost to cover the floor = Number of tiles x Cost per tile

Cost to cover the floor = 4500 tiles x 23.25 = 104625

Therefore, the cost to cover the floor with these tiles will be 104625.

answered
User Wumpz
by
8.6k points
1 vote

Answer:

surface to be tiled: 4.5*3.6=16.2m²

we calculate the area of ​​a square tile of 6cm: 6²=36cm²=0.0036m²

number of tiles to buy: 16.2/0.0036=4500

cost: 23.25*4500=104625

Explanation:

answered
User Prashant Kanse
by
9.1k points

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