asked 124k views
5 votes
A manager wishes to build a 3-sigma range chart for a process. The sample size is five, the mean of sample means is 47.50, and the average range is 10.30. From Table S6.1, the appropriate value of D3 is 0, and D4 is 2.115. What are the UCL and LCL, respectively, for this range chart? (Do not round intermediate calculations. Round final answer to two decimal places.)

A. 78.40 and 16.60

B. 9.75 and 0.00

C. 12.42 and 8.19

D. 21.78 and 0.00

E. 57.80 and 37.20

1 Answer

2 votes

Answer:

D. 21.78 and 0.00

Explanation:

Mean = M = 47.50

Average Range = R = 10.30

Sample Size = 5

D3 = 0

D4 = 2.115

Now,

UCL = (D4)(R0

UCL = 21.78

LCL = (D3)(R)

LCL = 0

Hence the correct option is D

answered
User Tim Richard
by
8.6k points
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