Question

The products of two consecutive integers is 156 . Set up the quadratic equation in the form ax^(2)+bx+c=0 that solves the problem but do not solve.

Answer 1

x² + x - 156 = 0

Explanation:

x = first integer

x + 1 = second consecutive integer

x(x+1) = 156

x² + x = 156

Rearrange the equation to the standard quadratic form ax² + bx + c = 0 by subtracting 156 from both sides:

x² + x - 156 = 0

Where, a = 1, b = 1, and c = -156.