Answer: a) {15, 24, 33, 42, 51} b) 5/36 c) {11, 12, 13, 21, 22, 31} d) 1/6
Explanation:
a) The set E has to contain the possible pair of numbers that show up the dice that sum up to 6. This includes 15, 24, 33, 42, 51 so the set E is
{15, 24, 33, 42, 51}
b) Since there are 5 pairs out of a possible 36, the probability that the sum of numbers that are shown face up on both sides are 6 is
5/36
c) The set F has to contain the possible pair of numbers that show up the dice that sum up to at most 4. This includes 11, 12, 13, 21, 22, 31 so the set F is
{11, 12, 13, 21, 22, 31}
d) Since there are 5 pairs out of a possible 36, the probability that the sum of numbers that are shown face up on both sides are at most 4 is 6/36 or 1/6