Question

In a closed system, an object with a mass of 10 kg moves at a velocity of 5. 4 m/s. It collides with a second object that has a mass of 12 kg and that is moving in the opposite direction with a velocity of 3. 5 m/s. What is the total momentum of the system after the collision?.

Answer 1

Okay, let's solve this step-by-step:

* We have two objects colliding in a closed system

* Object 1 has mass m1 = 10 kg and velocity v1 = 5.4 m/s

* Object 2 has mass m2 = 12 kg and velocity v2 = 3.5 m/s (in opposite direction)

* Total momentum before collision:

p1 = m1*v1 = 10*5.4 = 54 kg.m/s

p2 = m2*v2 = 12*(-3.5) = -42 kg.m/s

Total momentum before collision = p1 + p2 = 54 - 42 = 12 kg.m/s

* In a closed system with an elastic collision, the total momentum after collision equals the total momentum before collision.

* Therefore, the total momentum after collision is: 12 kg.m/s.

So the total momentum of the system after the collision is 12 kg.m/s.